题目:

找出大于10的最小的2进制,8进制,10进制都是回文数的最小的数。回文数指的是正读和反读都是一样的数,例如:33,10001,123454321...

思路:

先转换进制,然后统一处理成字符串进行比较

解答:

PHP

function execute(){
    $x = 11;
    while (1) {
        if ($x == strrev($x)
            && decbin($x) == strrev(decbin($x))
            && decoct($x) == strrev(decoct($x))) {
            break;
        }
        $x += 2;
    }
    return $x;
}

$result = execute(); echo $result;

golang

package main

import ( "fmt" "strconv" )

func main() { result := Execute() fmt.Println(result) }

func Execute() string { xStr := "" for x := 11; ; x += 2 { xStr = strconv.Itoa(x) xBin := strconv.FormatInt(int64(x), 2) xOct := strconv.FormatInt(int64(x), 8) if xStr == Reverse(xStr) && xBin == Reverse(xBin) && xOct == Reverse(xOct) { break } } return xStr }

// 字符串翻转 func Reverse(s string) string { runes := []rune(s) for from, to := 0, len(runes)-1; from < to; from, to = from+1, to-1 { runes[from], runes[to] = runes[to], runes[from] } return string(runes) }